lldb: use stdio transport by default

This commit is contained in:
Dmitry Sharshakov 2021-09-06 13:49:31 +03:00
parent 507a1f8dd6
commit 413e477dc2
3 changed files with 10 additions and 11 deletions

View file

@ -98,6 +98,7 @@ pub struct DebugAdapterConfig {
pub name: String,
pub transport: String,
pub command: String,
#[serde(default)]
pub args: Vec<String>,
pub port_arg: Option<String>,
pub templates: Vec<DebugTemplate>,

View file

@ -116,12 +116,16 @@ impl Client {
// TODO: do we need bufreader/writer here? or do we use async wrappers on unblock?
let writer = BufWriter::new(process.stdin.take().expect("Failed to open stdin"));
let reader = BufReader::new(process.stdout.take().expect("Failed to open stdout"));
let errors = BufReader::new(process.stderr.take().expect("Failed to open stderr"));
let errors = process.stderr.take().map(BufReader::new);
Self::streams(
Box::new(BufReader::new(reader)),
Box::new(writer),
Some(Box::new(BufReader::new(errors))),
// errors.map(|errors| Box::new(BufReader::new(errors))),
match errors {
Some(errors) => Some(Box::new(BufReader::new(errors))),
None => None,
},
id,
Some(process),
)

View file

@ -22,10 +22,8 @@ indent = { tab-width = 4, unit = " " }
[language.debugger]
name = "lldb-vscode"
transport = "tcp"
transport = "stdio"
command = "lldb-vscode"
args = []
port-arg = "-p {}"
[[language.debugger.templates]]
name = "binary"
@ -91,10 +89,8 @@ indent = { tab-width = 2, unit = " " }
[language.debugger]
name = "lldb-vscode"
transport = "tcp"
transport = "stdio"
command = "lldb-vscode"
args = []
port-arg = "-p {}"
[[language.debugger.templates]]
name = "binary"
@ -121,10 +117,8 @@ indent = { tab-width = 2, unit = " " }
[language.debugger]
name = "lldb-vscode"
transport = "tcp"
transport = "stdio"
command = "lldb-vscode"
args = []
port-arg = "-p {}"
[[language.debugger.templates]]
name = "binary"